1.

In triangle `A B C ,`let `/_c=pi/2dot`If `r`is the inradius and `R`is circumradius of the triangle, then `2(r+R)`is equal to`a+b`(b) `b+c``c+a`(d) `a+b+c`

Answer» Here, `C = pi/2`
Now, `c = 2RsinC = 2R`
`=>R = c/2`
`=>2R = c->(1)`
`r = (s-c)tan(C/2) = (s-c)tan(pi/4)`
`=>r = s-c`
`=>2r = 2s-2c = a+b+c-2c = a+b-c`
From (1),
`=>2r = a+b-2R`
`=>2(r+R) = a+b.`


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