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In `triangleABC`, if D is the midpoint of BC and E is the midpoint of AD then `ar(triangleBED)` = ? A. `(1)/(2)ar(triangleABC)`B. `(1)/(3)ar(triangleABC)`C. `(1)/(4)ar(triangleABC)`D. `(2)/(3)ar(triangleABC)` |
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Answer» Correct Answer - C Median AD divides `triangleABC` into two triangles of equal area. `thereforear(triangleABD)=ar(triangleADC)=(1)/(2)ar(triangleABC).` In `triangleABD`, median BE divides it into two `triangle` of equal area. `therefore ar(triangleBED)=ar(triangleABE)=(1)/(2)ar(triangleABD)=(1)/(4)ar(triangleABC)`. |
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