InterviewSolution
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InterviewSolution
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In two dice game, the player take turns to roll both dice, they can roll as many times as they want in one turn. A player scores the sum of the two dice thrown and gradually reaches a higher score as they continue to roll. If a single number 1 is thrown on either die, the score for that whole turn is lost. Two dice are thrown simultaneously. What is the probability of getting the sum as an even number ? |
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Answer» `(3)/(4)` (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) NUMBER of all possible outcomes in all case, `n(S)=6xx6=36` Favourable outcome are {2, 4, 6, 8, 10, 12}. We may get as follows `{(1, 1), (1, 3), (3, 1), (2, 2), (1, 5), (5, 1), (2, 4), (4, 2), (3, 3), (2, 6), (6, 2), (3, 5), (5, 3), (4, 4), (6, 4), (4, 6), (5, 5), (6, 6)}` Thus number of favourable outcomes, `n(E_(1))=18` P(sum as an even number), `P(E_(1))=(n(E_(1)))/(n(S))=(18)/(36)=(1)/(2)` Thus (d) is correct option. |
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