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In what ratio is the segment joining A (2, -3) and B (5, 6) divided by the x-axis? |
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Answer» Let point P on the x-axis divides the line segment joining the points A and B the ratio m : n Consider P lies on x-axis having coordinates (x, 0). x = (m × 5 + n x2)/ (m + n) x = (5m + 2n ) / (m + n) 5m + 2n = x(m + n ) (5 – x)m + (2 – x)n = 0 ….(1) And, y = 0 = (m × 6 + n(– 3))/ (m+n) 0 = (6m – 3n ) /(m + n) 6m – 3n = 0 6m = 3n or m/n = 3/6 = 1/2 P divides AB in the ratio 1:2. => m = 1 and n = 2 From (2) (5 – x) + (2 – x)(2) = 0 5 – x + 4 – 2x = 0 3x = 9 x = 3 Hence coordinates are (3,0) |
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