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In which case will the efficiency of a carnot cycle be higher : When the hot body temperature is increased by `Delta T`, or when the cold body temperature is decreased by the same magnitude ? |
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Answer» The efficiency is given is `eta = (T_1 - T_2)/(T_1), T_1 gt T_2` Now in the two cases the efficiencies are `eta_h = (T_1 + Delta T - T_2)/(T_1 + Delta T), T_1` encreased `eta_l = (T_1 - T_2 + Delta T)/(T_1), T_2` decreased Thus `eta_h lt n_l`. |
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