1.

In which of the following, there are maximum number of atoms?

Answer»

18 g `H_(2)O`
18 g `O_(2)`
18 g `CO_(2)`
18 g `CH_(4)`

Solution :Mole of `CH_(4) = (18)/(16)`
= 1.125 mole
= `1.125 xx 5 xx 6.022 xx 10^(23)`
= `33.87 xx 10^(23)`
= `3.387 xx 10^(24)` atoms


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