Input a string and find the number of space , words , characters

1.	Input a string and find the number of space , words , characters
Answer» ong>Answer: Hope this helps Explanation: import java.util.Scanner; public class Exercise38 { public static void MAIN(String[] args) { String test = "AA kiu, I swd skieo 236587. GH kiu: sieo?? 25.33"; count(test); } public static void count(String X){ char[] ch = x.toCharArray(); INT letter = 0; int space = 0; int num = 0; int other = 0; for(int i = 0; i < x.length(); i++){ if(Character.isLetter(ch[i])){ letter ++ ; } else if(Character.isDigit(ch[i])){ num ++ ; } else if(Character.isSpaceChar(ch[i])){ space ++ ; } else{ other ++; } } System.out.println("The string is : Aa kiu, I swd skieo 236587. GH kiu: sieo?? 25.33"); System.out.println("letter: " + letter); System.out.println("space: " + space); System.out.println("number: " + num); System.out.println("other: " + other); } }

Answer»

ong>Answer:

Hope this helps

Explanation:

import java.util.Scanner;

public class Exercise38 {

public static void MAIN(String[] args) {

String test = "AA kiu, I swd skieo 236587. GH kiu: sieo?? 25.33";

count(test);

}

public static void count(String X){

char[] ch = x.toCharArray();

INT letter = 0;

int space = 0;

int num = 0;

int other = 0;

for(int i = 0; i < x.length(); i++){

if(Character.isLetter(ch[i])){

letter ++ ;

}

else if(Character.isDigit(ch[i])){

num ++ ;

}

else if(Character.isSpaceChar(ch[i])){

space ++ ;

}

else{

other ++;

}

System.out.println("The string is : Aa kiu, I swd skieo 236587. GH kiu: sieo?? 25.33");

System.out.println("letter: " + letter);

System.out.println("space: " + space);

System.out.println("number: " + num);

System.out.println("other: " + other);

}

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