Inside a spacecraft travelling at a speed of 0.8c with respect to the earth, the time interval between two events on the earth is measured to be 30 hrs. What would the time interval be if the spacecraft was travelling at a speed of 0.9c.

Inside a spacecraft travelling at a speed of 0.8c with respect to the

1.	Inside a spacecraft travelling at a speed of 0.8c with respect to the earth, the time interval between two events on the earth is measured to be 30 hrs. What would the time interval be if the spacecraft was travelling at a speed of 0.9c.
Answer» e time interval will be 19.11 hrs. Explanation:Here length contraction will take place when we TRAVEL with speed comparable to speed of light L = Lo √ 1− V^ 2 / c^2 L = Lo √ 1− (0.81 c)^ 2 / c^2 =Lo × 0.6t = L / VT = 0.6 Lo / 0.8 CLO = 0.8 c x 30 hrs / 0.6 = 40 c.hrsIn the SECOND case the speed is 0.9 c then L = Lo √ 1− v^ 2 / c^2 L = Lo √ 1 − (0.81 c)^ 2 / c^2 = 0.43 Lot = L/v = 0.43 Lo / 0.9 c = 0.43 x 40 c.hrs/ 0.9 c t = 19.11 hrs Thus the time interval will be 19.11 hrs.

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Inside a spacecraft travelling at a speed of 0.8c with respect to the earth, the time interval between two events on the earth is measured to be 30 hrs. What would the time interval be if the spacecraft was travelling at a speed of 0.9c.​

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Inside a spacecraft travelling at a speed of 0.8c with respect to the earth, the time interval between two events on the earth is measured to be 30 hrs. What would the time interval be if the spacecraft was travelling at a speed of 0.9c.