1.

Is any term of  sequence 5, 11, 17, 23, …. will be 299?

Answer»

Given A.P.

5, 11, 17, 23, ……..

First term (a) = 5

Common difference (d) = 11 – 5 = 6

nth term (an) = 299

Formula an = a + (n – 1)d

⇒ 299 = 5 + (n – 1) × 6

⇒ 299 – 5 = (n – 1) 6

⇒ 294 = (n – 1) 6

⇒ n – 1 = 294/6

⇒ n – 1 = 49

⇒ n = 49 + 1

⇒ n = 50

n is whole no.

∴ Hence, 299 is 50th term of sequence 5, 11, 17, 23 ….



Discussion

No Comment Found