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Is any term of sequence 5, 11, 17, 23, …. will be 299? |
Answer» Given A.P. 5, 11, 17, 23, …….. First term (a) = 5 Common difference (d) = 11 – 5 = 6 nth term (an) = 299 Formula an = a + (n – 1)d ⇒ 299 = 5 + (n – 1) × 6 ⇒ 299 – 5 = (n – 1) 6 ⇒ 294 = (n – 1) 6 ⇒ n – 1 = 294/6 ⇒ n – 1 = 49 ⇒ n = 49 + 1 ⇒ n = 50 n is whole no. ∴ Hence, 299 is 50th term of sequence 5, 11, 17, 23 …. |
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