1.

Is it true for any sets A and B, P(A) ∪ P(B) = P(A ∪ B)? Justify your answer.

Answer»

Let A = {φ{a}}, and B = {b}

∴ A∪B = {a, b}

P(A) = {φ,{a}}, P(B) = {φ, {b}}

and P(A∪B) = {φ,{a},{b} {a,b}}………………. (1)

and P(A)∪P(B) = {φ,{a},{b}} ………………. (2)

From (1) and (2), we get, P(A∪B) ≠ P(A)∪P{B)



Discussion

No Comment Found

Related InterviewSolutions