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Is it true for any sets A and B, P(A) ∪ P(B) = P(A ∪ B)? Justify your answer. |
Answer» Let A = {φ{a}}, and B = {b} ∴ A∪B = {a, b} P(A) = {φ,{a}}, P(B) = {φ, {b}} and P(A∪B) = {φ,{a},{b} {a,b}}………………. (1) and P(A)∪P(B) = {φ,{a},{b}} ………………. (2) From (1) and (2), we get, P(A∪B) ≠ P(A)∪P{B) |
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