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Is it true that for any sets A and B, P (A) ∪ P (B) = P (A ∪ B)? Justify your answer. |
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Answer» It is a False statement. Let, A = {3} and B = {4} Then, P(A) = {ϕ , {3}} And P(B) = {ϕ , {4}} ∴ P(A) ∪ P (B) = {ϕ , {1}, {2}} Now, A ∪ B = {1, 2} And P(A ∪ B) = {ϕ , {1}, {2}, {1, 2}} Hence, P(A) ∪ P(B) ≠ P (A ∪ B) |
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