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is9. A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming that the accelerationuniform, find () the acceleration and (ii) the distance travelled by the train for attaining this velocityirt

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please send the answer again

speed of train is 72km/h = 72*5/18 = 20m/snow, time taken is 5 min = 300sec

so, a = V-u/t = 20/300 1/15 m/s²

now distance travelled iss = 1/2*a*t² = 1/2*(1/15)*(300)² = = 300*300/30 = 3000m



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