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Ismein aap sirf distance find karke batao mujhe kitna aata hai |
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Answer» Answer: Answer Initial speed of the three-wheeler, U = 36 km/h = 10 m/s Final speed of the three-wheeler, v = 0 m/s Time, t = 4 s Mass of the three-wheeler, m = 400 kg Mass of the DRIVER, m' = 65 kg Total mass of the SYSTEM, M = 400 + 65 = 465 kg Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as: v = u + at ∴ a = v - u / t = 0-10/4 = -2.5 m/s2 The negative sign indicates that the velocity of the three-wheeler is decreasing with time. Using NEWTON’s second law of motion, the net force acting on the three-wheeler can be calculated as: F = Ma = 465 × (–2.5) = –1162.5 N The negative sign indicates that the force is acting against the direction of motion of the three-wheeler. |
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