It is propssed to use the nucles fasion `_(1)^(2) H +_(1)^(2) H rarr _(2)^(4) He` in a nucleas of `200MW` rating if the energy from the above reaction is used with a `25` per cast effecincy in the rector , low maney game of deuterium fiel will be needed per day (The masses of `_(1)^(2)H and _(4)^(2) He are 2.0141`atomic mass unit and `4.0028`atyomic mass uniot repertively)

It is propssed to use the nucles fasion `_(1)^(2) H +_(1)^(2) H rarr _

1.	It is propssed to use the nucles fasion `_(1)^(2) H +_(1)^(2) H rarr _(2)^(4) He` in a nucleas of `200MW` rating if the energy from the above reaction is used with a `25` per cast effecincy in the rector , low maney game of deuterium fiel will be needed per day (The masses of `_(1)^(2)H and _(4)^(2) He are 2.0141`atomic mass unit and `4.0028`atyomic mass uniot repertively)
Answer» Correct Answer - A energy required per day ` E = p xx 1 = 200 xx 10^(9) xx 24 xx 60 xx 60` `= 1.728 xx 10^(13)J` energy released per fusion reaction `= [ 2 (2.0141)-4.0026] xx 931.5 MeV` `= 23.15 xx 10^(-13)J` `:. ` No of fusion reactions required `= (1.728 xx 10^(13))/(38.15 xx 10^(-13)) = 0.045 xx 10^(26)` :.` No of deuterium atoms required `= 2 xx 0.045 xx 10^(26) = 0.09 xx 10^(26)` number of deterium atom `= (0.09 xx 10^(26))/(6.02 xx 10^(23)) = 14.95` `:.`Mass in gram of deterium atom `= 14.95 xx 2 = 29.9 g` But the efficiency is `25%` Therefore, the efficiency mass required` = 199.6 g`

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