It the enthalpy of vaporization of benzene is `308/ kJ mol^(-1)` at boiling point `(80^(@)C)`, calculate the entroy `(j mol^(-1) K^(-1))` in changing it from liquid to vapor.A. 308B. 0.873C. 0.308D. 873

It the enthalpy of vaporization of benzene is `308/ kJ mol^(-1)` at bo

1.	It the enthalpy of vaporization of benzene is `308/ kJ mol^(-1)` at boiling point `(80^(@)C)`, calculate the entroy `(j mol^(-1) K^(-1))` in changing it from liquid to vapor.A. 308B. 0.873C. 0.308D. 873
Answer» Correct Answer - D According to thermodynamics, `Delta_(vap) S = (Delta_(vap) H)/(T_(b))` `= (308 xx 10^(3) J mol^(-1))/((273 + 80) K)` `= 873 K^(-1) mol^(-1)` Note that `T_(b)` is the boiling point of benzene.

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It the enthalpy of vaporization of benzene is `308/ kJ mol^(-1)` at boiling point `(80^(@)C)`, calculate the entroy `(j mol^(-1) K^(-1))` in changing it from liquid to vapor.A. 308B. 0.873C. 0.308D. 873

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