Saved Bookmarks
| 1. |
Ithe photoelectric work function of a metal surface is 4.14 EV .the cutoff wavelength for this is |
Answer» Cutoff wavelength = 0.3 micrometerExplanation: Given: Photoelectric work function of a METAL surface is 4.14 EV Find: Cutoff wavelength. Solution: W = 4.14 e V Converting W to JOULES, we get: 4.14 * 1.6 * 10^-19 J W = H c / λo Where λo is the cutoff wavelength, h = 6.626 * 10-34, and c is the speed of light in vacuum. So λo = h c / W = 6.626 * 10^-34 * 3 * 10^8 / (4.14 * 1.6 * 10^-19) = (6.626 * 3 / 4.14 * 1.6) * 10^-7 = 3.0009 * 10^-7 m = 0.3 micrometer Cutoff wavelength = 0.3 micrometer |
|