John has bought a 4 Gbyte MP3 player. (You may assume: 1 byte = 8 bits, 1 Mbyte = 1024 kbytes and 1Gbyte = 1024 Mbytes) (i) We can assume that each song lasts 3 minutes and is recorded at 128 kbps (kilobits per second). How much memory is required per song?

John has bought a 4 Gbyte MP3 player. (You may assume: 1 byte = 8 bi

1.	John has bought a 4 Gbyte MP3 player. (You may assume: 1 byte = 8 bits, 1 Mbyte = 1024 kbytes and 1Gbyte = 1024 Mbytes) (i) We can assume that each song lasts 3 minutes and is recorded at 128 kbps (kilobits per second). How much memory is required per song?
Answer» second in 3 minutes is3×60=180song RECORD 128 kbps then total memory is 180×128=23040 kb PER 180 second now convert 23040kb into mb23040÷8=2,880this mean 2.8 MB per song