Just when a motorcycle begins move from rest in a certain direction, a

1.	Just when a motorcycle begins move from rest in a certain direction, a motorcar moving with a uniform velocity in the same direction overtakes it. The difference in their displacements in 18 sec isIn the above problem at what time do they meet again?
Answer» The distance travelled by car in 15 s = Area of AOAC =(1/2)×15×45 = 337.5 m Distance travelled by scooter in 15 s = Area of rectangle OCEF =15×30 = 450 m Thus, DIFFERENCE between distance travelled by them = 450 m - 337.5 m = 112.5 m b. Let after TIME t from start car will CATCH, up the scooter. In time t, the distance travelled by them are equal. Distance travelled by car = (1/2)×15×45 + 45( t - 15) Distance travelled by scooter = 30t(1/2)×15×45 + 45(t - 15) = 30t which gives t = 22.5 s Distance travelled by car or scooter in 22.5 s = 30 x 22.5 = 675 m So the car catches the scooter when both are at 675 m from the starting POINT.

Just when a motorcycle begins move from rest in a certain direction, a motorcar moving with a uniform velocity in the same direction overtakes it. The difference in their displacements in 18 sec isIn the above problem at what time do they meet again?

Answer»

The distance travelled by car in 15 s

= Area of AOAC

=(1/2)×15×45 = 337.5 m

Distance travelled by scooter in 15 s

= Area of rectangle OCEF

=15×30 = 450 m

Thus, DIFFERENCE between distance travelled by them = 450 m - 337.5 m = 112.5 m

b. Let after TIME t from start car will CATCH, up the scooter. In time t, the distance travelled by them are equal.

Distance travelled by car = (1/2)×15×45 + 45( t - 15)

Distance travelled by scooter = 30t(1/2)×15×45 + 45(t - 15) = 30t

which gives t = 22.5 s

Distance travelled by car or scooter in 22.5 s = 30 x 22.5

= 675 m

So the car catches the scooter when both are at 675 m from the starting POINT.

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Just when a motorcycle begins move from rest in a certain direction, a motorcar moving with a uniform velocity in the same direction overtakes it. The difference in their displacements in 18 sec isIn the above problem at what time do they meet again?​

The distance travelled by car in 15 s

= Area of AOAC

=(1/2)×15×45 = 337.5 m

Distance travelled by scooter in 15 s

= Area of rectangle OCEF

=15×30 = 450 m

Thus, DIFFERENCE between distance travelled by them = 450 m - 337.5 m = 112.5 m

b. Let after TIME t from start car will CATCH, up the scooter. In time t, the distance travelled by them are equal.

Distance travelled by car = (1/2)×15×45 + 45( t - 15)

Distance travelled by scooter = 30t(1/2)×15×45 + 45(t - 15) = 30t

which gives t = 22.5 s

Distance travelled by car or scooter in 22.5 s = 30 x 22.5

= 675 m

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Just when a motorcycle begins move from rest in a certain direction, a motorcar moving with a uniform velocity in the same direction overtakes it. The difference in their displacements in 18 sec isIn the above problem at what time do they meet again?