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`k_(a) ` wavelength emitted by an atom of atomic number `E= 11` is `lambda` find the atomic number for an atomic that amils `k_(a)` radiation with wavwlength `43`.A. `Z = 6`B. `Z = 4`C. `Z = 11`D. `Z = 44` |
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Answer» Correct Answer - A For K_(q) , (1)/(lambda) prop (Z- 1)^2) `From `(i), (lambda_(2))/(lambda_(1)) -((Z_(1) - 1)^(2))/((Z_(2) - 1) ^(2)) rArr ( 4lambda)/(lambda) = ((11 - 1)^(2))/((Z_(2) - 1)^(2))` `rArr Z_(2) - 1 = (10)/(2) rArr Z_(2) = 6` |
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