1.

K_(C ) for the reaction (1)/(2)N_(2)(g)+(3)/(2)H_(2)(g) hArr NH_(3(g)) is

Answer»

`K_(c )=([NH_(3)])/([N_(2)][H_(2)])`
`K_(c )=([N_(2)][H_(2)])/([NH_(3)])`
`K_(c )=([NH_(3)])/([N_(2)]^(1/2)[H_(2)]^(3/2))`
`K_(c )=([N_(2)]^(1/2)[H_(2)]^(3/2))/([NH_(3)])`

Solution :`(1)/(2)N_(2)+(3)/(2)H_(2) HARR NH_(3)`
`K_(c )=([NH_(3)])/([N_(2)]^(1/2)[H_(2)]^(3/2))`


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