1.

km g-9.01111 sMass of earth is 80 times that of moon and the radiusof moon. If 'g' on the surfathe surface of the moon.7.of earth is 4 times thatce of the earth is 9.8 mls?. Calculate its vaiue o

Answer»

the acceleration due to gravity on moon is g ' and that on earth is g.We know that,g = GM/R2where,G > gravitation constantM > mass of earthR > radius of earthlet us introduce a new parameter, D = diameter of earth = 2R=> R = D/2

so,g '= 4GM/D2................(1)

also,g ' = Gm/r2where,G > gravitation constantm > mass of moonr > radius of moonlet us introduce a new parameter, D = diameter of moon =2r=> r = d/2

so,g '=4Gm/d2................(2)

Now,it is given,M:m = 80:1as Earth's mass is 80 times moon's.and,D:d = 4:1as their diameters are in the given ration in the question.

by devidingequation 1 by 2,(1)/(2)

g/g ' = [4GM/D2]/[4Gm/d2]= [M/D2]/[m/d2]= [M:m]*[d2:D2]= ​[M:m]/[D:d]280/1]/[4/1]2= (80)/(16)= 5

Now,we have,g:g ' = 5:1so,g ' = g/5= 9.81/5= 1.9802≈1.98 m/s2

same with mine .okaay



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