`KMnO_(4)` oxidizes `X^(n+)` ion to `XO_(3)^(-)` itself changing to `Mn^(2+)` in acid solution. `2.68xx10^(-3)` moel of `K_(2)Cr_(2)O_(7)` was required `1.61xx10^(-3)` mole of `MnO_(4)^(-)`. What is the value of `n` ? Also calcualte the atomic mass of `X`, if the weight of `1g` equivalent of `XCl_(n)` is 56

`KMnO_(4)` oxidizes `X^(n+)` ion to `XO_(3)^(-)` itself changing to `M

1.	`KMnO_(4)` oxidizes `X^(n+)` ion to `XO_(3)^(-)` itself changing to `Mn^(2+)` in acid solution. `2.68xx10^(-3)` moel of `K_(2)Cr_(2)O_(7)` was required `1.61xx10^(-3)` mole of `MnO_(4)^(-)`. What is the value of `n` ? Also calcualte the atomic mass of `X`, if the weight of `1g` equivalent of `XCl_(n)` is 56
Answer» Correct Answer - `2,97`

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