L.c.m Of Two Prime Numbers X And Y (x>y) Is 161. The Value Of 3y-x Is

1.	L.c.m Of Two Prime Numbers X And Y (x>y) Is 161. The Value Of 3y-x Is?
Answer» H. C. F of two prime numbers is 1. Product of numbers = 1 x 161 = 161. Let the numbers be a and B . Then , ab= 161. Now, co-primes with product 161 are (1, 161) and (7, 23). Since x and y are prime numbers and x >y , we have x=23 and y=7. Therefore, 3y-x = (3 x 7)-23 = -2. H. C. F of two prime numbers is 1. Product of numbers = 1 x 161 = 161. Let the numbers be a and b . Then , ab= 161. Now, co-primes with product 161 are (1, 161) and (7, 23). Since x and y are prime numbers and x >y , we have x=23 and y=7. Therefore, 3y-x = (3 x 7)-23 = -2.

L.c.m Of Two Prime Numbers X And Y (x>y) Is 161. The Value Of 3y-x Is?

Answer»

H. C. F of two prime numbers is 1.

Product of numbers = 1 x 161 = 161.

Let the numbers be a and B . Then , ab= 161.

Now, co-primes with product 161 are (1, 161) and (7, 23).

Since x and y are prime numbers and x >y ,

we have x=23 and y=7.

Therefore, 3y-x = (3 x 7)-23 = -2.

H. C. F of two prime numbers is 1.

Product of numbers = 1 x 161 = 161.

Let the numbers be a and b . Then , ab= 161.

Now, co-primes with product 161 are (1, 161) and (7, 23).

Since x and y are prime numbers and x >y ,

we have x=23 and y=7.

Therefore, 3y-x = (3 x 7)-23 = -2.