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l r balls each of mass m impinge elastically each second ona surface with velocity u. The average force experiencedby the surface will bea. mnu b. 2 mnu c. 4 mnu d. mnul2lined |
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Answer» Given :mass of each ball = m kgvelocity= u m/sIn elastic collision :Change in momentum= mu-(-mu)=mu+mu=2muFor N balls change in momentum:Δp=N*2mu Rate of change of momentum=Δp/t=N2mu/1 sec=N2mu According to Netwon's Second LawF=Δp/t F=N2mu B.......................... |
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