InterviewSolution
Saved Bookmarks
| 1. |
l uu hot existmarkIn Young's experiment the ratio of intensityat the maxima and minima in the interferencepattern is 36:16. What is the ratio of thewidths of the two slits? |
|
Answer» If the width of the slits are A₁ and A₂, the amplitude will also be A1 and A2. The maximum amplitude, A' will happen when constructive interference happensA' = (A₁ + A₂)The maximum amplitude, A will happen when destructive interference happensA = (A₁ - A₂) We know that intensity is proportional to the square of amplitude.I1/I2 = A'^2/A^2 9/25 = [(A1+A2)/(A1-A2)]^2(9/25)^1/2 = (A1+A2)/(A1-A2)(A1+A2)/(A1-A2) = 3/5A1/A2 = 5+3/5-3 = 8/2 A1:A2 = 4:1 |
|