InterviewSolution
Saved Bookmarks
| 1. |
laced two blocks in contactthe 10 kg blochs State br' S oN two10 kg block. (ii) If the abov e this blocke 20 kgsmooth table are placed5. On a() Ahorizontal force of5.0 N is applied on the 20 kgNthe 10 kg block.the rher sState by what force this block presseswforce is applied onthe other sideof the hen by 5.020ね10 tagwhat force the20 kg blockwill press the 10 kg block?Ans. (i) (10/6) N towards right,(ii) (206) N towards right. |
|
Answer» F=ma => That is your magnitude my dear friend. But acceleration is a vector, (x,y,z) direction. If you have a space between the blocks and then contact is made, then you're dealing with momentum. p=mv. So, that is then p=m((v-u)/t). |
|