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\({\left( {1 + {\rm{tanA}}} \right)^2} + {\left( {1{\rm{\;}} - {\rm{\;tanA}}} \right)^2}\) is equal to1). 2cosec2A2). cosec2A3). sec2A4). 2 sec2A |
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Answer» $(\RIGHTARROW {\rm{\;}}{\LEFT( {1 + {\rm{tanA}}} \right)^2} + {\left( {1{\rm{\;}} - {\rm{\;tanA}}} \right)^2})$ $(\Rightarrow 1 + 2{\rm{tanA}} + {\tan ^2}{\rm{A}} + 1{\rm{\;}} - {\rm{\;}}2{\rm{tanA}} + {\tan ^2}{\rm{A}} = 2 + 2{\tan ^2}{\rm{A\;}})$ $(= 2\left( {1 + {\rm{TA}}{{\rm{N}}^2}{\rm{\;A}}} \right) = {\rm{\;}}2{\sec ^2}{\rm{A}})$ |
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