1.

\left. \begin{array} { l l } { ( 10 / 3 ) m } & { ( 2 ) } \\ { 6 m } & { ( 4 ) } & { 4 m } \end{array} \right.

Answer»

Use the formula for displacement in nth second

Sn=u+a/2(2n-1)

here u=0 as it is starting from rest, a=4/3m/s^2

S3=0+4/6(2(3)-1)

S3=4/6(5)

S3=20/6

S3=10/3 m



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