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\left. \begin{array} { l l } { ( 10 / 3 ) m } & { ( 2 ) } \\ { 6 m } & { ( 4 ) } & { 4 m } \end{array} \right. |
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Answer» Use the formula for displacement in nth second Sn=u+a/2(2n-1) here u=0 as it is starting from rest, a=4/3m/s^2 S3=0+4/6(2(3)-1) S3=4/6(5) S3=20/6 S3=10/3 m |
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