1.

Let ` A={x:x in N , x^2-9=0}and B={x:x in Z , x^2-9=0}`. Show that `A ne B`.

Answer» `x^2-9=0rArr (x+3)(x-3)=0rArr B={x:-3or x=3`.
`therefore A={x:x in N , x^2-9=0}={3} " "[because -3in N] `
and ` B={x:x in Z, x^2-9=0}={-3,3}`.
Hence, `A ne B`.


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