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Let ` A={x:x in N , x^2-9=0}and B={x:x in Z , x^2-9=0}`. Show that `A ne B`. |
Answer» `x^2-9=0rArr (x+3)(x-3)=0rArr B={x:-3or x=3`. `therefore A={x:x in N , x^2-9=0}={3} " "[because -3in N] ` and ` B={x:x in Z, x^2-9=0}={-3,3}`. Hence, `A ne B`. |
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