1.

Let A = { x | x

Answer» Correct Answer - D
Given
`A={x:xle9, x inN}={1,2,3,4,5,6,7,8,9}`
Total possible multiple of 3 are ,brgt 3, 6, 9, 12, 15, 18, 21, 24, 27
But 3 and 27 are not possible because 3 and 27 can not be express as such that a+b+c is multiple of 3
`6rarr1+2+3`
`9rarr2+3+4,5+3+1,6+2+1`
`12rarr9+2+1,8+3+1,7+1+4,7+2+3`,
6+4+2,6+5+1,5+4+3`
`15rarr9+4+2,9+5+1,8+6+1,8+5+2`,
8+4+3,7+6+2,7+5+3,6+5+4`
`18rarr9+8+1,9+7+2,9+6+3`,
`9+5+4,8+7+3,8+6+4,7+6+5`
`21rarr9+8+4,9+7+5,8+7+6`
`24rarr9+8+7`
Hence, total largest possible subsets are 30.


Discussion

No Comment Found

Related InterviewSolutions