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Let A = { x | x |
Answer» Correct Answer - D Given `A={x:xle9, x inN}={1,2,3,4,5,6,7,8,9}` Total possible multiple of 3 are ,brgt 3, 6, 9, 12, 15, 18, 21, 24, 27 But 3 and 27 are not possible because 3 and 27 can not be express as such that a+b+c is multiple of 3 `6rarr1+2+3` `9rarr2+3+4,5+3+1,6+2+1` `12rarr9+2+1,8+3+1,7+1+4,7+2+3`, 6+4+2,6+5+1,5+4+3` `15rarr9+4+2,9+5+1,8+6+1,8+5+2`, 8+4+3,7+6+2,7+5+3,6+5+4` `18rarr9+8+1,9+7+2,9+6+3`, `9+5+4,8+7+3,8+6+4,7+6+5` `21rarr9+8+4,9+7+5,8+7+6` `24rarr9+8+7` Hence, total largest possible subsets are 30. |
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