InterviewSolution
Saved Bookmarks
| 1. |
Let ABC be a triangle, the position vectors of whose vertices are `7hatj+10hatk,-1hati+6hatj+6hatk` and `-4hati+9hatj+6hatk`. Then, `DeltaABC` isA. isoscelesB. equilateralC. right angledD. none of these |
|
Answer» Correct Answer - A::C We have, `AB=-hati-hatj-4hatk,BC=-3hati+3hatj` and `CA=4hati-2hatj+4hatk`. therefore, `|AB|=|BC|=3sqrt(2) and |CA|=6`. Clearly, `|AB|^(2)+|BC|^(2)=|AC|^(2)` Hence, the triangle is right angled isoscels triangle. |
|