Let `alpha` and `beta(alpha – InterviewSolution

InterviewSolution

1.	Let `alpha` and `beta(alpha
Answer» `x^2+bx+c=0` `x=(-bpmsqrt(b^2-4c))/2` `b^2-4c>b^2` `sqrt(b^2-4c)>\|b\|` `\|alpha\|>beta` `-alpha>beta` `alpha+beta=alphabeta-b+C<0` `alpha^2beta+alphabeta^2=alphabeta(alpha+beta)<0` option 2 is correct.

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