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Let `alpha=som^(-1)((36)/(85)),beta=cos^(-1)(4/5)a n dgamma=tan^(-1)(8/(15))`then`cotalpha+cotbeta+cotgamma=cotalphacotbetacotgamma``tanalphatanbeta+tanbetatangamma+tanalphatangamma=1``tanalpha+tanbeta+tangamma=tanalphatanbetatangamma``cotalphacotbeta+cotbetacotgamma+cotalphacotgamma=1` |
Answer» `alpha=sin^(-1)(36/85),sinalpha=36/85,tanalpha=36/77` `beta=cos^(-1)(4/5)=sinbeta=3/5,tanbeta=3/4` `gamma=tan^(-1)(8/15),tangamma=8/15` `tan(alpha+beta+gamma)=(sumtanalpha-pitanalpha)/(1-sumtanalphatanbeta)` `=(36/77+3/9+8/15-36/77*3/4*8/15)/(1-(36/77*3/4+8/15*3/4+8/15*36/77))` `tan(alpha+beta+gamma)=oo` `alphaa+beta+gamma=pi/2` `1=tanalphatanbeta+tanbetatangamma+tanalphatangamma` `cotalpha+cotbeta+cotgamma=cotalphacotbetacotgamma`. |
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