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    				| 1. | Let E and F be two independent events. The probability that exactly one of them occurs is `11//25` and the probability of none of them occurring is `2//25.` If P(T) denotes the probability of occurrence of the event T, thenA. `P(E)=4/5,P(F)=3/5`B. `P(E)=1/5,P(F)=2/5`C. `P(E)=2/5,P(F)=1/5`D. `P(E)=3/5,P(F)=4/5` | 
| Answer» Correct Answer - A::D Let `P(E)=eand P(F)=f` `P(EuuF)-P(EnnF)=11/25` `impliese+f-2ef=11/25" "(1)` `P(barEnnbarF)=2/25` `implies(1-e)(1-f)=2/25" "(2)` From (1) and (2), `ef=12/25and e+f=7/5` Solving, we get `e=4/5,f=3/5or e=3/5,f=4/5` | |