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    				| 1. | Three numbers are chosen at random without replacement from `{1,2,3,...,8}.` The probability that their minimum is 3, given that maximum is 6, is:A. `3/8`B. `1/5`C. `1/4`D. `2/5` | 
| Answer» Correct Answer - B Given set of numbers is `{1,2,3,4,5,6,7,8}` We have to select three numbers Let us assume that event A `to` inselected three numbers minimum is 3 event B `to` in selected three numbers maximum is 6 We have to find P (A/B). `P(A//B)=(P(AnnB))/(P(B))=(n(AnnB))/(N(B))` `AnnB` = in selected three numbers, minimum is 3 and maximum is 6 `therefore` The remaining number is either 4 or 5 `therefore n(AnnB)=2` n(B) = selecting two numbers from `1,2,3,4,5` (as maximum of numbers is 6) `=""^(5)C_(2)` `thereforeP(A//B)=(n(AnnB))/(n(B))=(2)/(""^(5)C_(2))=1/5` | |