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One ticket is selected at random from 50 ticketsnumbered 00, 01, 02, ... , 49. Then the probability that the sum of thedigits on the selected ticket is 8, given that the product of these digits iszero, equals(1) 1/14 (2) 1/7(3) 5/14(4) 1/50A. `1/14`B. `1/7`C. `5/14`D. `1/50` |
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Answer» Correct Answer - A `S={00,01,02,....,49}` Let A be the event that the sum of the digits on the selected ticket is 8. Then `A={08,17,26,35,44}` Let B be the event that the product of the digits is zero. Than `B={00,01,02,03,...,09,10,20,30,40}` `thereforeAnnB={8}` The required probability is `P(A//B)=(P(AnnB))/(P(B))` `=(1/50)/(14/50)=1/14` |
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