1.

One ticket is selected at random from 50 ticketsnumbered 00, 01, 02, ... , 49. Then the probability that the sum of thedigits on the selected ticket is 8, given that the product of these digits iszero, equals(1) 1/14 (2) 1/7(3) 5/14(4) 1/50A. `1/14`B. `1/7`C. `5/14`D. `1/50`

Answer» Correct Answer - A
`S={00,01,02,....,49}`
Let A be the event that the sum of the digits on the selected ticket is 8. Then
`A={08,17,26,35,44}`
Let B be the event that the product of the digits is zero. Than
`B={00,01,02,03,...,09,10,20,30,40}`
`thereforeAnnB={8}`
The required probability is
`P(A//B)=(P(AnnB))/(P(B))`
`=(1/50)/(14/50)=1/14`


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