1.

Let `f:[-100pi,100pi] ->[-1,1]` be defined by `f(theta)=sin theta` Then what is the number of values of `theta in [-100pi, 1000pi]` for which `f(theta)=0`A. 1000B. 1101C. 1100D. 1110

Answer» Correct Answer - B
`f(theta)=0`, if `theta` is an integral multiple of `pi`. From `-100pi` to `0pi` there are 101 values of `theta` for which `f(theta)=0`.
From `pi` to `1000pi`, there are 1000 values for which `f(theta)=0`
so, total values number is `101+1000=1101`


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