Let `f(x) = {x-1)^2 sin(1/(x-1)-|x|`,if `x!=1` and -1, if `x=1` 1valued function. Then, the set of pointsf, where `f(x)` is not differentiable, is .... .

Let `f(x) = {x-1)^2 sin(1/(x-1)-|x|`,if `x!=1` and -1, if `x=1` 1value

1.	Let `f(x) = {x-1)^2 sin(1/(x-1)-\|x\|`,if `x!=1` and -1, if `x=1` 1valued function. Then, the set of pointsf, where `f(x)` is not differentiable, is .... .
Answer» Correct Answer - x = 0 Given, `f(x) = {{:((x-1)^(2) sin. 1/((x-1))-\|x\|", if "x ne 1),(" -1, if " x = 1):}` As, `f(x) = {{:((x-1)^(2)sin. 1/(x-1) -x", "0le x-{1}),((x-1)^(2)sin 1/((x-1))+x", " x lt 0),(" -1 , " x= 1):}` Here, f(x) in not differentiable at x = 0 due to \|x\|. Thus, f(x) is not differentiable at x = 0 .