Let P = (-1, 0), Q = (0, 0) and R = (3, `3sqrt3`) be three points. The equation of the bisector of the angle PQRA. `(sqrt(3))/(2)x+y=0`B. `x+sqrt(3)y=0`C. `sqrt(3)x+y=0`D. `x+(sqrt(3))/(2)y=0`

Let P = (-1, 0), Q = (0, 0) and R = (3, `3sqrt3`) be three points. The

1.	Let P = (-1, 0), Q = (0, 0) and R = (3, `3sqrt3`) be three points. The equation of the bisector of the angle PQRA. `(sqrt(3))/(2)x+y=0`B. `x+sqrt(3)y=0`C. `sqrt(3)x+y=0`D. `x+(sqrt(3))/(2)y=0`
Answer» The line segment `QR` makes an angle of `60^(@)` with the positive direction of `X`-axis. So, the bisector of the angle `PQR` will make an angle of `60^(@)` with the negative direction of `X`-axis it will therefore have angle of inclination of `120^(@)` and so, its equation is `y-0=tan120^(@)(x-0)` `impliesy=-sqrt(3)x` `impliesy+sqrt(3)x=0`

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Let P = (-1, 0), Q = (0, 0) and R = (3, `3sqrt3`) be three points. The equation of the bisector of the angle PQRA. `(sqrt(3))/(2)x+y=0`B. `x+sqrt(3)y=0`C. `sqrt(3)x+y=0`D. `x+(sqrt(3))/(2)y=0`

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