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Let `P={theta:sintheta-costheta=sqrt2cos theta}and Q={theta:sintheta+costheta=sqrt2sintheta}` be two ses. Then,A. `PsubQ and A - P ne phi`B. `QcancelsubP`C. `PcancelsubQ`D. P = Q |
Answer» Correct Answer - D `P:sintheta-costheta=sqrt(2)costhetaimpliestantheta=sqrt(2)+1` `Q:sintheta+costheta=sqrt(2)sinthetaimpliestantheta=(1)/(sqrt(2)-1)=sqrt(2)+1` `therefore P = Q` |
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