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Let `veca= 2 hati + 3hatj - 6hatk, vecb = 2hati - 3hatj + 6hatk and vecc = -2 hati + 3hatj + 6hatk`. Let `veca_(1)` be the projection of `veca on vecb and veca_(2)` be the projection of `veca_(1) on vecc` . Then`veca_(1).vecb` is equal toA. `-41`B. `-41//7`C. 41D. 287 |
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Answer» Correct Answer - a `veca_(1).vecb= (-41)/49 (2hati - 3hatj + 6hatk) . (2hati - 3hatj + 6hatk) =-41` |
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