Let `vecr, veca, vecb` and `vecc` be four non-zero vectors such that `vecr.veca=0, |vecrxxvecb|=|vecr||vecb|,|vecrxxvecc|=|vecr||vecc|` then `[(veca, vecb, vecc)]=`A. |a||b||c|B. `-|a||b||c|`C. 0D. none of these

Let `vecr, veca, vecb` and `vecc` be four non-zero vectors such that `

1.	Let `vecr, veca, vecb` and `vecc` be four non-zero vectors such that `vecr.veca=0, \|vecrxxvecb\|=\|vecr\|\|vecb\|,\|vecrxxvecc\|=\|vecr\|\|vecc\|` then `[(veca, vecb, vecc)]=`A. \|a\|\|b\|\|c\|B. `-\|a\|\|b\|\|c\|`C. 0D. none of these
Answer» Correct Answer - c `vecr.veca = 0, \|vecr xx vecb\| = \|vecr\|\|vecb\| and \|vecr xx vecc\|` `\|vecr\|\|vecc\|` ` [ veca vecb vecc] =0`

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Let `vecr, veca, vecb` and `vecc` be four non-zero vectors such that `vecr.veca=0, |vecrxxvecb|=|vecr||vecb|,|vecrxxvecc|=|vecr||vecc|` then `[(veca, vecb, vecc)]=`A. |a||b||c|B. `-|a||b||c|`C. 0D. none of these

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