

InterviewSolution
Saved Bookmarks
1. |
LEVEL-2EAMPLE s Aand B are friends and their ages differ by 2 years. A's father D is twice as old asnt es frvice as old as his sister C. The age of D and C differ by 40 years. Find the age |
Answer» let the age of A = x age of B = x+2 since, A's father D is twice as old as ASo, age of D = 2×x = 2x and since B is twice as old as his sisterSo, age of C = age of B / 2 = (x+2)/2 according to the question,The age of D and C differ by 40yrs.it means, age of D - age of C = 40 => 2x - [(x+2)/2] = 40 => 2x - (x+2)/2 = 40 => 4x/2 - (x+2)/2 = 40 => (4x - x + 2)/2 = 40 => 3x+2/2 = 40 => 3x + 2 = 40 × 2 => 3x = 80 - 2 => x = 78/3= 26 So, age of A = x = 26yr.s age of B = x + 2 = 26 + 2 = 28yr.s |
|