InterviewSolution
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InterviewSolution
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lf `asin^-1 x -bcos^-1 x=c,`then `asin^-1 x +bcos^-1` equal to |
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Answer» Correct Answer - D `a sin^(-1) x - b cos^(-1) x = c` We have `b sin^(-1) x + b cos^(-1) x = (bpi)/(2)` Adding `(a + b) sin^(-1) x = (bpi)/(2) + c` `rArr sin^(-1) x = (((bpi)/(2)) + c)/(a + b) = (b pi + 2c)/(2(a + b))` `:. cos^(-1) x = (pi)/(2) - (b pi + 2c)/(2(a + b)) = (pi a - 2c)/(2(a + b))` `rArr a sin^(-1) x + b cos^(-1) x = (pi ab + c(a - b))/(a + b)` |
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