1.

Light travels with a velocity `1.5xx10^(8)m//s` in a medium. On entering `2^(nd)` medium its velocity becomes `0.75xx10^(8)m//s`. What is the refractive index of the `2^(nd)` medium with respect to the first medium.

Answer» Given : `v_(1)=1.5xx10^(8)m//s`
`v_(2)=0.75 xx 10^(8) m//s`
To find : `" "_(2)n_(1)=`?
Formula : ` " "_(2)n_(1)=(v_(1))/(v_(2))`
Solution : `" "_(2)n_(1)=(1.5xx10^(8))/(0.75 xx 10^(8))`
`" "_(2)n_(1)=2`
Refractive index of `2^(nd)` medium with respect to `1^(st)` is 2.


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