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Light travels with a velocity `1.5xx10^(8)m//s` in a medium. On entering `2^(nd)` medium its velocity becomes `0.75xx10^(8)m//s`. What is the refractive index of the `2^(nd)` medium with respect to the first medium. |
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Answer» Given : `v_(1)=1.5xx10^(8)m//s` `v_(2)=0.75 xx 10^(8) m//s` To find : `" "_(2)n_(1)=`? Formula : ` " "_(2)n_(1)=(v_(1))/(v_(2))` Solution : `" "_(2)n_(1)=(1.5xx10^(8))/(0.75 xx 10^(8))` `" "_(2)n_(1)=2` Refractive index of `2^(nd)` medium with respect to `1^(st)` is 2. |
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