1.

Light wave described by the equation `200 V//m sin (1.5xx10^15 s^(-1) t cos (0.5xx10^15 s^(-1) t` falls metal surface having work function 2.0 eV. Then, the maximum kinetic energy photoelectrons isA. `3.27eV`B. `2.2eV`C. `2.85eV`D. none of these

Answer» Correct Answer - D
`omega_(max) = 1.5xx10^(15) rad/s = 2pif_(max)`
`:. f_(max) = (1.5xx10)^15/(2pi) Hz`
`E = (hf_(max)/(1.6xx10^(-19) eV`
`=(6.63xx10^(-34)xx1.5xx10^(15)/(2pixx1.6xx10^(-19) eV`
`~~1.0 eV`
Since, E lt W, no photoemission can take place.


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