\(\lim\limits_{x \to 0}\frac{e^x-1}{x}\) =(a) e (b) nxn - 1 (c) 1 (d) 0

\(\lim\limits_{x \to 0}\frac{e^x-1}{x}\) =(a) e (b) nxn - 1 (c) 1

1.	\(\lim\limits_{x \to 0}\frac{e^x-1}{x}\) =(a) e (b) nxn - 1 (c) 1 (d) 0
Answer» (c) 1 (By formula)