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`lim_(x->pi)((sin3x-3sinx)/((pi-x)^3))` |
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Answer» Correct Answer - `-1` Given limit `=lim_(xto pi)((3sinx-4sin^(3)x-3sinx))/((pi-x)^(3))` `=lim_(xto pi)(-4sinx)/((pi-x)^(3))=lim_(thetato0)(-4sin^(3)(pi+theta))/((-theta)^(3))where (x-pi)=theta` `=-4lim_(thetato0)((sintheta)/(theta))=(-4xx1)=-4.` |
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