Liquid water freezes at 273 K under external pressure of 1 atm. The process is at equilibrium `H_(2)O (I) hArr H_(2)O (s)` at 273 K & 1 atm However it was required to calculate the thermodyanamic parameters of the fusion prcess occuring at same pressure & different temperature. Using the following data, answer the question that follow. `d_("ice") = 0.9 gm//c c, d_(H_(2)O(I)) = 1 gm//c c, C_(P) [H_(2)O(s)] = 36.4 JK^(-1) mol^(-1), C_(P) [H_(2)O (I) ] = 75.3 JK^(-1) mol^(-1), Delta H_("fusion") = 6008.2 J mol^(-1)` The value of `'DeltaH_("fusion")'` at 263 K & 1 atm will be :A. `+6008.0 J "mole"^(-1)`B. `5619.2 J "mole"^(-1)`C. `-5619.2 J "mole"^(-1)`D. `6619.2 J K^(-1) mol^(-1)`

Liquid water freezes at 273 K under external pressure of 1 atm. The pr

1.	Liquid water freezes at 273 K under external pressure of 1 atm. The process is at equilibrium `H_(2)O (I) hArr H_(2)O (s)` at 273 K & 1 atm However it was required to calculate the thermodyanamic parameters of the fusion prcess occuring at same pressure & different temperature. Using the following data, answer the question that follow. `d_("ice") = 0.9 gm//c c, d_(H_(2)O(I)) = 1 gm//c c, C_(P) [H_(2)O(s)] = 36.4 JK^(-1) mol^(-1), C_(P) [H_(2)O (I) ] = 75.3 JK^(-1) mol^(-1), Delta H_("fusion") = 6008.2 J mol^(-1)` The value of `'DeltaH_("fusion")'` at 263 K & 1 atm will be :A. `+6008.0 J "mole"^(-1)`B. `5619.2 J "mole"^(-1)`C. `-5619.2 J "mole"^(-1)`D. `6619.2 J K^(-1) mol^(-1)`
Answer» Correct Answer - B `H_(2)O (l) hArr H_(2)O (s)` `DeltaC_(p) = 36.4 - 75.3 = - 38.9 J.K^(-1) mol^(-1)` `Delta H_(273) - DeltaH_(263) = Delta C_(p) [T_(2) - T_(1)]`

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