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Liquid water freezes at 273 K under external pressure of 1 atm. The process is at equilibrium `H_(2)O (I) hArr H_(2)O (s)` at 273 K & 1 atm However it was required to calculate the thermodyanamic parameters of the fusion prcess occuring at same pressure & different temperature. Using the following data, answer the question that follow. `d_("ice") = 0.9 gm//c c, d_(H_(2)O(I)) = 1 gm//c c, C_(P) [H_(2)O(s)] = 36.4 JK^(-1) mol^(-1), C_(P) [H_(2)O (I) ] = 75.3 JK^(-1) mol^(-1), Delta H_("fusion") = 6008.2 J mol^(-1)` `' Delta S_("fusion")'` at 263 K & 1 atm will be:A. `22.01 JK^(-1) mol^(-1)`B. `22.84 JK^(-1) mol^(-1)`C. `21.36 JK^(-1) mol^(-1)`D. `20.557 JK^(-1) mol^(-1)`

Answer» Correct Answer - D
`Delta_("fussion") S = (Delta_("fussion")H)/(T_(f))`


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